(f:N \rightarrow N,f(x) = 2x + 3f:R \rightarrow R) = | MATH - LIMITS | SolveeIt

$f:N \rightarrow N,f(x) = 2x + 3f:R \rightarrow R$ =

$f(x) = (x - 1)(x - 2)(x - 3)$

– $A = \{ 1,2,3,4\},B = \{ a,b\}$

$A = \{ a,b,c\},$

$f:R \rightarrow R,$

Answer

$f:R \rightarrow R,$

Explanation

$\lim _ { x \rightarrow 0 }$ $\left( \frac { 0 } { 0 } \right.$ form $)$

L. Hospital rule

$\lim _ { x \rightarrow 0 }$ = $\lim _ { x \rightarrow 0 }$ $\frac { - 2 \sin ^ { 2 } ( x / 2 ) } { 4 \times ( x / 2 ) ^ { 2 } \times 3 }$

= $\frac { - 2 } { 3 \times 4 }$ = $- \frac { 1 } { 6 }$

Question: \(f:N \rightarrow N,f(x) = 2x + 3f:R \rightarrow R\) =...