Question
Question: Fluorine reacts with water to form: (A) \(\text{HF}\,\text{and }{{\text{O}}_{\text{2}}}\) (B) \...
Fluorine reacts with water to form:
(A) HFand O2
(B) HFand O3
(C) HFand OF2
(D) HF,O2and O3
Solution
Halogen are very reactive due to high electronegativity, high electron affinity and comparatively low bond energies.
- Fluorine has the highest reduction potential hence it is the strongest oxidizing agent.
Complete step by step answer:
- Fluorine and chlorine reacts with water while bromine and iodine are only sparingly soluble in water.
Fluorine gas reacts with water in normal temperature form hydrogen fluoride (HF) and release oxygen gas (O2), 2F2(g)+2H2O(l)→4F(aq)-+4H(aq)++O2(g)
- When a large amount of fluorine gas is reacted with water molecule at very high temperature, it will release ozone gas with HF
3F2(g)+3H2O(l)→4F(aq)-+4H(aq)++O3(g)
When fluorine reacts with water in the presence of sunlight at very low temperature it forms HOF and HF.
F2+H2Ohv−40∘CHOF+HF
So, the correct answer is “Option A”.
Additional information: Halogen reacts with water in a very different manner. Fluorine oxidises water molecules by releasing oxygen gas. Chlorine and bromine react with water molecules to form hydra acid(HX) and hypohalous acid (HOX).
X2+H2O→HOX+HX !!!! X=Cl, Br !!!!
- Iodine does not react with water, instate I− ions can be oxidised by oxygen in an acidic medium.
Note: Hydride of fluorine HF is liquid because of strong hydrogen bonding ,while other halogen hydracids (HX) are gaseous in nature. The abnormal behaviour of fluorine is due to its small size, high electronegativity and low F-F bond dissociation energy.
- Fluorine forms only one oxyacid HOF, because of its high electronegativity and small size and represents only one covalency.