Question
Question: Fluid is flowing with velocity 4m/s in a cylinder of diameter 8 cm. It is connected to a pipe with i...
Fluid is flowing with velocity 4m/s in a cylinder of diameter 8 cm. It is connected to a pipe with its end tip of diameter 2 cm. Calculate the velocity of the fluid at this free end.
A. 4m/s
B. 8m/s
C. 32m/s
D. 64m/s
Solution
When fluid is flowing through a pipe, the volume has to be conserved per unit time. This means the rate of volume entering must be equal to the rate of exiting. This result is called the equation of continuity which is a very important result of a principle known as Bernoulli’s principle.
Formula used: dtdV=A1v1=A2v2
Complete step-by-step solution
__
As shown in the above diagram, we have the fluid getting enter in the thicker tube and getting exit from the narrow tube. Now, according to the equation of continuity, A1v1=A2v2
Given: d1=8cm⟹A1=4π(8)2
And d2=2cm⟹A2=4π(2)2
Also v1=4m/s
Hence putting these values in equation A1v1=A2v2, we get;
4π×82×4=4π×22×v2
⟹v2=82=64m/s.
Thus, option D. is correct.
Additional information: The termdtdVrepresents the rate of flow of fluid. It means the total volume of fluid flow per unit time. Hence we can calculate this term if we know the variation of volume with time. Equation of continuity plays a very important role in fluid mechanics. Even in the case of varying cross-sectional areas, we could get the point to point relation between area and velocity of the fluid molecule at that point. The measuring area of cross-section is an easier task, compared to the velocity. Hence using this equation, we can analyze the complex situation of the velocity behavior of the fluid.
Note: There are certain assumptions that Bernoulli assumed while deriving this theorem. This includes that fluid must be incompressible and the flow of fluid must be laminar flow. This type of fluid is called an ideal fluid. But practically, it’s very difficult for fluid to behave like an ideal fluid.