Question

Five point charges each of value +Q are placed on five vertices of a regular hexagon of side L. What is the magnitude of the force on a point charge of value – q placed at the centre of the hexagon

• A. $k\frac{Q^{2}}{L^{2}}$
• B. $k\frac{Q^{2}}{4L^{2}}$
• C. Zero
• D. Information is insufficient

Answer 1

Answer: (A)

$k\frac{Q^{2}}{L^{2}}$

Answer 2

Four charges cancels the effect of each other, so the net force on the charge placed at centre due to remaining fifth charge is

$F = k\frac{Q^{2}}{L^{2}}$