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Question

Mathematics Question on Probability

Five persons entered the lift cabin on the ground floor of an eight floor house. Suppose that each of them independently and with equal probability can leave the cabin at any floor beginning with the first, then the probability of all 55 persons leaving at different floors is

A

7P575\frac{^{7}{{P}_{5}}}{{{7}^{5}}}

B

757P5\frac{{{7}^{5}}}{^{7}{{P}_{5}}}

C

66P5\frac{6}{^{6}{{P}_{5}}}

D

5P555\frac{^{5}{{P}_{5}}}{{{5}^{5}}}

Answer

7P575\frac{^{7}{{P}_{5}}}{{{7}^{5}}}

Explanation

Solution

Since, each person can leave the cabin at any floor. Total number of ways, 75{{7}^{5}}
\therefore Required probability =7P575=\frac{^{7}{{P}_{5}}}{{{7}^{5}}}