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Question

Question: Five particles of mass = 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligi...

Five particles of mass = 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is

A

1 kg m2

B

0.1 kg m2

C

2 kg m2

D

0.2 kg m2

Answer

0.1 kg m2

Explanation

Solution

We will not consider the moment of inertia of disc because it doesn't have any mass so moment of inertia of five particle system I=5mr2=5×2×(0.1)2=0.1kgm2I = 5mr^{2} = 5 \times 2 \times (0.1)^{2} = 0.1kg ⥂ - ⥂ m^{2}.