Solveeit Logo

Question

Question: Five mole of a diatomic gas is kept at temperature\[T\]. The volume of the gas varies according to t...

Five mole of a diatomic gas is kept at temperatureTT. The volume of the gas varies according to the law, V=aT2V = a{T^{ - 2}}, where a is positive constant. The final temperature of the gas is found to be 5T5T, what amount of heat is supplied to the gas?
A. 5RT5RT
B. (5/2)RT(5/2)RT
C. (10/3)RT(10/3)RT
D. 10RT10RT

Explanation

Solution

As we know that for the diatomic gas, number of molecules are 5, initial temperature is T. Also V varies as V=aT2V = a{T^{ - 2}} where aa is positive constant and also final temperature is 5T. The atomicity is the number of atoms combined to form the molecule to remain in the stable state. Mono-atomic gas are the atoms which have 1 atomicity and diatomic has 2 atomicity.

Complete step by step answer:
Number of mole=5mole = 5mole
Temperature = TT (Initial temperature)
V=aT2V = a{T^{ - 2}}(Here V is the volume of gas)
Final temperature = 5T
As we know that
PVT=constant = c\dfrac{{PV}}{T} = {\text{constant = c}}
So, PVT=constant = c\dfrac{{PV}}{T} = {\text{constant = c}}
PVC=T\dfrac{{PV}}{C} = T
Substitute the value of temperature, we get-
V=aT2V = a{T^{ - 2}}
We can write-
VT2=aV{T^2} = a
P×(PVC)2=a\Rightarrow P \times {\left( {\dfrac{{PV}}{C}} \right)^2} = a
P2V3=constant\Rightarrow{P^2}{V^3} = {\text{constant}}
PV32=C2\Rightarrow P{V^{\dfrac{3}{2}}} = {C_2}----- (1)

Now compare this equation with PVN=ConstantP{V^N} = {\text{Constant}}, we get-
N=32N = \dfrac{3}{2}
Now for finding the value of C (Molar heat capacity)
C=(CVRN1)C = ({C_V} - \dfrac{R}{{N - 1}})
C=5R2R321\Rightarrow C = \dfrac{{5R}}{2} - \dfrac{R}{{\dfrac{3}{2} - 1}}
C=R2\Rightarrow C = \dfrac{R}{2}
Now, heat supplied,ΔQ=n×C×ΔT\Delta Q = n \times C \times \Delta T
Here QQ is the heat supplied, NN is the number of moles, CC is the heat capacity and ∆t is the change in initial and final temperature.

By substituting all the values, we get,
5×R2×(5TT)5 \times \dfrac{R}{2} \times \left( {5T - T} \right)
5×R2×(4T)\Rightarrow 5 \times \dfrac{R}{2} \times \left( {4T} \right)
10RT\therefore 10RT

So, option (D) is correct.

Note: Heat capacity is an extensive property. It is a physical property which is defined as the amount of heat that is supplied to the given mass of material to produce a unit change in its temperature. SI unit of heat capacity is Joules/kJoules/k.It is also known as thermal capacity.