Question

Five digit numbers are formed using digits 1, 2, 3, 4, 5, 6 & 8. What is probability that they have even digits at both the ends?

• A. $\frac { 4 } { 7 }$
• B. $\frac { 3 } { 7 }$
• C. $\frac { 2 } { 7 }$
• D. None

Answer 1

Answer: (C)

$\frac { 2 } { 7 }$

Answer 2

T.C. = 7.6.5.4.3

F.C. = E ---E = (⁴C₂ $2 !$ ) 5.4.3

p = $\frac { 2 } { 7 }$