Question

Five coins whose faces are marked 2, 3 are tossed. The chance of obtaining a total of 12 is

• A. $\frac { 1 } { 32 }$
• B. $\frac { 1 } { 16 }$
• C. $\frac { 3 } { 16 }$
• D. $\frac { 5 } { 16 }$

Answer 1

Answer: (D)

$\frac { 5 } { 16 }$

Answer 2

Condition for sum of 12 is 2, 2, 2, 3, 3

$\therefore$Required probability $= { } ^ { 5 } C _ { 3 } \left( \frac { 1 } { 2 } \right) ^ { 3 } \left( \frac { 1 } { 2 } \right) ^ { 2 }$