Question

First overtone frequency of a closed pipe of length $'l_1'$ is equal to the $2^{nd}$ harmonic frequency of an open pipe of length $'l_2'$ .The ratio $\frac{l_1}{l_2} =$

• A. $\frac{3}{4}$
• B. $\frac{4}{3}$
• C. $\frac{3}{2}$
• D. $\frac{2}{3}$

Answer 1

Answer: (A)

$\frac{3}{4}$

Answer 2

$\frac{3V}{4I_1} = \frac{2V}{2I_2}$
$\frac{l_1}{l_2} = \frac{3}{4}$