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Question: Find $[VD]_{mix}$ of a gaseous mixture of $O_3$ and $O_2$. Molar ratio of $O_3$ to $O_2$ is 1:2...

Find [VD]mix[VD]_{mix} of a gaseous mixture of O3O_3 and O2O_2. Molar ratio of O3O_3 to O2O_2 is 1:2

A

566\frac{56}{6}

B

1123\frac{112}{3}

C

2243\frac{224}{3}

D

563\frac{56}{3}

Answer

563\frac{56}{3}

Explanation

Solution

The average molar mass of the mixture is calculated as follows:

Mmix=13(48)+23(32)=48+643=1123 g/molM_{mix} = \frac{1}{3}(48) + \frac{2}{3}(32) = \frac{48 + 64}{3} = \frac{112}{3} \text{ g/mol}

Vapour density is half of the molar mass:

[VD]mix=Mmix2=112/32=1126=563[VD]_{mix} = \frac{M_{mix}}{2} = \frac{112/3}{2} = \frac{112}{6} = \frac{56}{3}