Question

Find total number of compounds having X-O-X type bond:

$H_2S_4O_6$; $H_2S_2O_3$; $Cl_2O_7$, $N_2O_5$; $H_4P_2O_7$; $B_3N_3H_6$; $H_2S_2O_7$

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (D)

4

Answer 2

The question asks to find the total number of compounds from the given list that have an X-O-X type bond, where X is an atom. We need to examine the structure of each compound.

1. $H_2S_4O_6$ (Tetrathionic acid): The structure is $H O_3S - S - S - S - S O_3H$. This molecule contains a chain of four sulfur atoms and $S-O$ bonds, but no $S-O-S$ linkage.
2. $H_2S_2O_3$ (Thiosulfuric acid): The structure is $H O - \underset{S}{\stackrel{O}{\parallel}}S - O H$. This molecule contains a $S=S$ double bond and $S-O$ bonds, but no $S-O-S$ linkage.
3. $Cl_2O_7$ (Dichlorine heptoxide): The structure is $O_3Cl - O - ClO_3$. This molecule contains a $Cl-O-Cl$ linkage, which is an X-O-X type bond where X = Cl.
4. $N_2O_5$ (Dinitrogen pentoxide): In the gaseous phase, the structure is $O_2N - O - NO_2$. This molecule contains a $N-O-N$ linkage, which is an X-O-X type bond where X = N.
5. $H_4P_2O_7$ (Pyrophosphoric acid): The structure is $(HO)_2 P(O) - O - P(O) (OH)_2$. This molecule contains a $P-O-P$ linkage, which is an X-O-X type bond where X = P.
6. $B_3N_3H_6$ (Borazine): This is a cyclic compound with the structure $(BH-NH)_3$. It is a six-membered ring of alternating boron and nitrogen atoms, with each atom bonded to a hydrogen atom. There are no oxygen atoms in this compound, so it cannot have an X-O-X bond.
7. $H_2S_2O_7$ (Disulfuric acid or Oleum): The structure is $H O_3S - O - S O_3H$. This molecule contains an $S-O-S$ linkage, which is an X-O-X type bond where X = S.

The compounds having an X-O-X type bond are $Cl_2O_7$, $N_2O_5$, $H_4P_2O_7$, and $H_2S_2O_7$. The total number of such compounds is 4.