Question
Question: Find three numbers in GP, whose product is 8 and their sum is \[\dfrac{{26}}{3}\]...
Find three numbers in GP, whose product is 8 and their sum is 326
Solution
Here in this question, we have to find the sum of finite geometric series. The geometric series is defined as the series with a constant ratio between the two successive terms. Then by considering the geometric series we have found the sum of the series.
Complete step by step solution:
In mathematics we have three types of series namely, arithmetic series, geometric series and harmonic series.
The geometric series is defined as the series with a constant ratio between the two successive terms. The finite geometric series is generally represented as a,ar,ar2,...,arn, where a is first term and r is a common ratio.
The first three terms of GP is generally given as ra, a and ar
The product of three terms is 8. So we have
ra×a×ar=8
On multiplying we have
⇒a3=8
On applying the cubic root to the above equation we have
⇒a=2
As we know that the sum of three terms is 326
So we have
ra+a+ar=326
On substituting the value of a, the above equation is written as
⇒r2+2+2r=326
On simplifying we have
Take 26r to LHS of the equation
⇒6r2+6r−26r+6=0 ⇒6r2−20r+6=0Divide the above equation by 3
⇒3r2−10r+3=0
The equation can be written as
⇒r=3and r=31
When a = 2 and r = 3, the geometric sequence is 32,2,6
When a = 2 and r = 31, the geometric sequence is 6,2,32
Note: Three different forms of series are arithmetic series, geometric series and harmonic series. For the arithmetic series is the series with common differences. The geometric series is the series with a common ratio. The sum is known as the total value of the given series.