Solveeit Logo

Question

Question: Find three numbers in GP, whose product is 8 and their sum is \[\dfrac{{26}}{3}\]...

Find three numbers in GP, whose product is 8 and their sum is 263\dfrac{{26}}{3}

Explanation

Solution

Here in this question, we have to find the sum of finite geometric series. The geometric series is defined as the series with a constant ratio between the two successive terms. Then by considering the geometric series we have found the sum of the series.

Complete step by step solution:
In mathematics we have three types of series namely, arithmetic series, geometric series and harmonic series.
The geometric series is defined as the series with a constant ratio between the two successive terms. The finite geometric series is generally represented as a,ar,ar2,...,arna,ar,a{r^2},...,a{r^n}, where a is first term and r is a common ratio.
The first three terms of GP is generally given as ar\dfrac{a}{r}, a and arar
The product of three terms is 8. So we have
ar×a×ar=8\dfrac{a}{r} \times a \times ar = 8
On multiplying we have
a3=8\Rightarrow {a^3} = 8
On applying the cubic root to the above equation we have
a=2\Rightarrow a = 2
As we know that the sum of three terms is 263\dfrac{{26}}{3}
So we have
ar+a+ar=263\dfrac{a}{r} + a + ar = \dfrac{{26}}{3}
On substituting the value of a, the above equation is written as
2r+2+2r=263\Rightarrow \dfrac{2}{r} + 2 + 2r = \dfrac{{26}}{3}
On simplifying we have

2+2r+2r2=263r 6+6r+6r2=26r  \Rightarrow 2 + 2r + 2{r^2} = \dfrac{{26}}{3}r \\\ \Rightarrow 6 + 6r + 6{r^2} = 26r \\\

Take 26r to LHS of the equation

6r2+6r26r+6=0 6r220r+6=0  \Rightarrow 6{r^2} + 6r - 26r + 6 = 0 \\\ \Rightarrow 6{r^2} - 20r + 6 = 0 \\\

Divide the above equation by 3
3r210r+3=0\Rightarrow 3{r^2} - 10r + 3 = 0
The equation can be written as

3r29rr+3=0 3r(r3)1(r3)=0 (r3)(3r1)=0  \Rightarrow 3{r^2} - 9r - r + 3 = 0 \\\ \Rightarrow 3r(r - 3) - 1(r - 3) = 0 \\\ \Rightarrow (r - 3)(3r - 1) = 0 \\\

r=3 \Rightarrow r = 3and r=13r = \dfrac{1}{3}
When a = 2 and r = 3, the geometric sequence is 23,2,6\dfrac{2}{3},2,6
When a = 2 and r = 13\dfrac{1}{3}, the geometric sequence is 6,2,236,2,\dfrac{2}{3}

Note: Three different forms of series are arithmetic series, geometric series and harmonic series. For the arithmetic series is the series with common differences. The geometric series is the series with a common ratio. The sum is known as the total value of the given series.