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Question

Mathematics Question on Sequence and series

Find three arithmetic means between 33 and 1919.

A

7,11,157, 11, 15

B

5,10,155, 10, 15

C

6,11,166, 11, 16

D

5,7,95, 7 , 9

Answer

7,11,157, 11, 15

Explanation

Solution

Let A1,A2,A3A_1, A_2, A_3 be 3A.M.??3 A.M.?? between 33 and 1919. Then 3,A1,A2,A3,193, A_1, A_2, A_3, 19 are in A.PA.P . whose common difference is d=1934=4d=\frac{ 19-3}{4} =4 A1=3+d\therefore A_{1} = 3+d A1=7\Rightarrow A_{1} = 7, A2=3+2d A_{2}= 3+2d A2=11\Rightarrow A_{2} = 11, A3=3+3d A_{3} = 3+3d A3=15 \Rightarrow A_{3}= 15, Hence, the required A.M.??A.M.?? are 7,11,157, 11, 15.