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Question

Question: Find the vertex, axis, focus, directrix, latus rectum of the parabola $y = x^2 - 2x + 3$....

Find the vertex, axis, focus, directrix, latus rectum of the parabola y=x22x+3y = x^2 - 2x + 3.

Answer
  • Vertex: (1,2)(1, 2)
  • Axis: x=1x = 1
  • Focus: (1,9/4)(1, 9/4)
  • Directrix: y=7/4y = 7/4
  • Latus Rectum Length: 11
Explanation

Solution

The equation y=x22x+3y = x^2 - 2x + 3 is rewritten by completing the square as (x1)2=y2(x-1)^2 = y-2. This matches the standard form (xh)2=4a(yk)(x-h)^2 = 4a(y-k) for a parabola opening upwards. By comparing, we identify the vertex (h,k)=(1,2)(h,k)=(1,2) and 4a=14a=1, so a=1/4a=1/4. The axis of symmetry is x=hx=h, which is x=1x=1. The focus is at (h,k+a)(h, k+a), yielding (1,9/4)(1, 9/4). The directrix is y=kay=k-a, which is y=7/4y=7/4. The length of the latus rectum is 4a|4a|, which is 1.