Question
Mathematics Question on Inverse Trigonometric Functions
Find the values of tan−1(tan43π)
Answer
tan−1(tan43π)
We know that tan−1(tanx)=xifx∈(−2π,2π), which is the principal value branch of tan−1x.
Here, 3π/4∉(-π/2'π/2)
Now,tan-1(tan(3π/4)can be written as:
tan-1(tan(3π/4)=tan-1[-tan(-3π/4)]=tan-1[-tan(π-π/4)]
=tan-1[-tanπ/4]=tan-1[tan(-π/4)] where,-π/4∈(-π/2'π/2)
therefore tan-1(tan(3π/4)=tan-1(tan(-π/4)=-π/4