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Question

Mathematics Question on Inverse Trigonometric Functions

Find the values of tan1(tan3π4)tan^{-1}(\tan\frac{3\pi}{4})

Answer

tan1(tan3π4)tan^{-1}(\tan\frac{3\pi}{4})
We know that tan1(tanx)=xifx(π2,π2)\tan^{-1}(\tan x)=x \,if x\in(-\frac{\pi}{2},\frac{\pi}{2}), which is the principal value branch of tan1x\tan^{-1}x.
Here, 3π/4∉(-π/2'π/2)
Now,tan-1(tan(3π/4)can be written as:
tan-1(tan(3π/4)=tan-1[-tan(-3π/4)]=tan-1[-tan(π-π/4)]
=tan-1[-tanπ/4]=tan-1[tan(-π/4)] where,-π/4∈(-π/2'π/2)
therefore tan-1(tan(3π/4)=tan-1(tan(-π/4)=-π/4