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Question

Mathematics Question on Angle Sum Property Of A Triangle

Find the value of the unknowns x and y in the following diagrams:
list of diagrams

Answer

(i) y+120°=180°y + 120° = 180° (Linear pair)
y=180°120=60x+y+50°=180°y= 180° - 120\degree = 60\degree x + y + 50° = 180° (Angle sum property) x+60°+50°x + 60° + 50°
= 180°x+110°=180°x180° x + 110° = 180° x
= 180°110°=70°180° - 110° = 70°


(ii) y=80°y = 80° (Vertically opposite angles)
y+x+50°=180°y + x + 50° = 180° (Angle sum property)
80°+x+50°=180°x+130=180°80° + x + 50° = 180° x + 130\degree = 180°
x=180°130º=50°x = 180° - 130 º = 50°


(iii) y+50°+60°=180°y + 50° + 60° = 180° (Angle sum property)
y=180°60°50°=70°x+y=180°y = 180° - 60° - 50° = 70° x + y = 180°
(Linear pair) x=180°y=180°70°x = 180° - y = 180° - 70°
= 110°110°


(iv) x = 60 º (Vertically opposite angles)
30°+x+y=180°30°+60°+y=180°y=180°30°60°=90°30° + x + y = 180° 30° + 60° + y =180° y = 180° - 30° - 60° = 90°


(v) y=90°y = 90° (Vertically opposite angles) x+x+y=180°x + x +y = 180° (Angle sum property)
2x+y=180°2x+90°=180°2x + y = 180° 2x+ 90° = 180°
x=902=45x = \frac{90\degree}{2}=45\degree


(vi)
triangle with angles
y=xy = x (Vertically opposite angles) a=xa = x (Vertically opposite angles) b=xb = x (Vertically opposite angles) a+b+ya + b + y = 180°180° (Angle sum property) x+x+x=180°x + x + x = 180°
3x=180°3x = 180°
x=1803=60x = \frac{180\degree}{3}=60\degree
y=x=60°y = x = 60°