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Question

Mathematics Question on Trigonometric Functions

Find the value of the trigonometric function sin(11π3).sin (-\frac{11π}{3}).

Answer

It is known that the values of tan x repeat after an interval of π or 180°.

sin(11π3)=sin(11π3+2×2π)=sin(π3)=32∴sin(-\frac{11{\pi}}{3})=sin(-\frac{11{\pi}}{3}+2×2{\pi})=sin(\frac{\pi}{3})=\frac{\sqrt3}{2}