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Question: Find the value of the following \[\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}=\] 1.\[\left( \d...

Find the value of the following ddx2πsinx=\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}=
1.(π180)cosx\left( \dfrac{\pi }{180} \right)\cos x
2.(190)cosx\left( \dfrac{1}{90} \right)\cos x
3.(π90)cosx\left( \dfrac{\pi }{90} \right)\cos x
4.(290)cosx\left( \dfrac{2}{90} \right)\cos x

Explanation

Solution

In order to differentiate ddx2πsinx\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}, firstly we will be converting the given degrees into radians by considering the value to 1{{1}^{\circ }}. Then after converting into radians, we will be differentiating the given function with respect to xx. After differentiating with respect to xx, upon solving it, we will be obtaining our required answer.

Complete step-by-step solution:
Now let us learn about radians and degrees in trigonometry. Generally, these are considered as the measures to measure the angles. A radian can be defined as the amount an angle should open to capture an arc of a circle's circumference of equal length to the circle’s radius. So one radian is equal to 180π180\pi degrees which is 53.7{{53.7}^{\circ }}. A degree can be divided into minutes and seconds. We can convert degrees into radians by Angle in radian = Angle in degree×π180\times \dfrac{\pi }{180}.
Now let us start differentiating the function given i.e. ddx2πsinx\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}.
Firstly let us consider it as y=ddx2πsinxy=\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}
Now let us convert the given function which is in degrees to radians.
We know that {{1}^{\circ }}$$$$=\dfrac{\pi }{180} radians.
So upon converting, we get
y=2πsin(π180)xy=\dfrac{2}{\pi }\sin \left( \dfrac{\pi }{180} \right)x
Now let us differentiate with respect to xx, on both sides. We get

& \Rightarrow y=\dfrac{2}{\pi }\sin \left( \dfrac{\pi }{180} \right)x \\\ & \Rightarrow \dfrac{dy}{dx}=\dfrac{2}{\pi }\cos \left( \dfrac{\pi }{180} \right)x\times \left( \dfrac{\pi }{180} \right) \\\ \end{aligned}$$ Because we know that $$\dfrac{d}{dx}\sin x=\cos x$$. Here we have used the multiplication rule of differentiation in order to differentiate. Now upon solving the obtained equation, we get $$\begin{aligned} & \Rightarrow \dfrac{1}{90}\cos \left( \dfrac{\pi }{180} \right)x \\\ & \Rightarrow \dfrac{1}{90}\cos {{x}^{\circ }} \\\ \end{aligned}$$ As we know that $${{1}^{\circ }}$$$$=\dfrac{\pi }{180}$$ radians. **$$\therefore $$ Option 2 is the correct answer.** **Note:** While differentiating the functions, we must apply the apt rule for solving. If we opt for complicated rules for solving, then the problem would be lengthy and time consuming. We have converted into radians for our easy calculation. The commonly committed error could be not differentiating correctly.