Question
Question: Find the value of the following \[\dfrac{d}{dx}\dfrac{2}{\pi }\sin {{x}^{\circ }}=\] 1.\[\left( \d...
Find the value of the following dxdπ2sinx∘=
1.(180π)cosx
2.(901)cosx
3.(90π)cosx
4.(902)cosx
Solution
In order to differentiate dxdπ2sinx∘, firstly we will be converting the given degrees into radians by considering the value to 1∘. Then after converting into radians, we will be differentiating the given function with respect to x. After differentiating with respect to x, upon solving it, we will be obtaining our required answer.
Complete step-by-step solution:
Now let us learn about radians and degrees in trigonometry. Generally, these are considered as the measures to measure the angles. A radian can be defined as the amount an angle should open to capture an arc of a circle's circumference of equal length to the circle’s radius. So one radian is equal to 180π degrees which is 53.7∘. A degree can be divided into minutes and seconds. We can convert degrees into radians by Angle in radian = Angle in degree×180π.
Now let us start differentiating the function given i.e. dxdπ2sinx∘.
Firstly let us consider it as y=dxdπ2sinx∘
Now let us convert the given function which is in degrees to radians.
We know that {{1}^{\circ }}$$$$=\dfrac{\pi }{180} radians.
So upon converting, we get
y=π2sin(180π)x
Now let us differentiate with respect to x, on both sides. We get