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Question

Question: Find the value of tan225°cot405° + tan765°cot675°:...

Find the value of tan225°cot405° + tan765°cot675°:

Explanation

Solution

Hint: These angles look absurd to you and you must be thinking, this is nowhere close to the 30°, 45°, 60° but here is a thing, if you look carefully to the angles you will find they are 2π + 45°, 4π ± 45° and3π2450\dfrac{3\pi }{2}-{{45}^{0}}. This way you can easily solve the expression.

Complete step by step answer:
We can write tan225° as tan (270° - 45°), cot405° as cot (360° + 45°), tan765° as tan (720° + 45°) and cot675° as cot (720° - 45°). Now, rewriting the expression given in question in terms of new angles as:
tan (270° - 45°)cot (360° + 45°) + tan (720° + 45°)cot(720° – 45°)
Now, 270° is3π2\dfrac{3\pi }{2}, 360° is 2π and 720° is 4π. So we are replacing these degree angles in the form of multiples of π as follows:
tan(3π2450)cot(2π+450)+tan(4π+450)cot(4π450)\tan \left( \dfrac{3\pi }{2}-{{45}^{0}} \right)\cot \left( 2\pi +{{45}^{0}} \right)+\tan \left( 4\pi +{{45}^{0}} \right)\cot \left( 4\pi -{{45}^{0}} \right)
Now, we know that tan θ and cot θ are positive in the first and third quadrants and in the other quadrants, they are negative. So, opening the brackets will give expression as follows:
cot45°cot45° + tan45° (-cot45°)
From the trigonometric angles value, we know that both tan45° and cot45° have the value of 1. So, substituting these values in above expression we get:
1(1) + 1(-1)
\Rightarrow 1 – 1
\Rightarrow 0
Hence, the value of the given expression in the question is 0.

Note: Instead of writing the angles that I have written above you can also write angles as shown below:
225° = 180° + 45°
405° = 450° – 45°
765° = 810° – 45°
675° = 630° + 45°
This way of writing angles is also correct because these forms of angles are in the same quadrant as I have shown above so the tan θ and cot θ conversion won’t change.