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Question

Question: Find the value of \( \tan {1080^ \circ } \)...

Find the value of tan1080\tan {1080^ \circ }

Explanation

Solution

Hint : First write the given angle in terms of 2nπ+θ2n{\pi } + \theta , multiple of 360 degrees or 2π2{\pi } radians, where n can be any natural number. And the value of tan of angle 2nπ+θ2n{\pi } + \theta will give tanθ\tan \theta itself. So divide the given angle appropriately.

Complete step-by-step answer :
Here the value of tan1080\tan {1080^ \circ } is positive because the angel falls in the first quadrant. And in the first quadrant all of the trigonometric ratios are positive. Tangent is positive in the first and third quadrants. Tangent is also a periodic function. So its value repeats after every π\pi radians. Tangent is one of most important functions in trigonometry. It is the inverse of cotangent function. Tangent function is also used to measure slopes of straight lines.
We are given to find the value of tan1080\tan {1080^ \circ } .
Tan is the ratio of sine to cosine or in a right angled triangle it is the ratio of opposite side and adjacent side to the given angle.
So here tan1080\tan {1080^ \circ } must be written in multiples of 360 degrees.
1080 degrees is 3 times 360 degrees.
This means tan1080=tan(3×360)\tan {1080^ \circ } = \tan \left( {3 \times {{360}^ \circ }} \right)
360 degrees is 2π2{\pi } radians.
tan1080=tan[(3×2π)+0]\Rightarrow \tan {1080^ \circ } = \tan \left[ {\left( {3 \times 2{\pi }} \right) + 0} \right]
tan1080=tan[(2×3×π)+0]\Rightarrow\tan {1080^ \circ } = \tan \left[ {\left( {2 \times 3 \times {\pi }} \right) + 0} \right]
The RHS of the above equation is in the form of tan(2nπ+θ)\tan \left( {2n\pi + {\theta }} \right) which is equal to tanθ\tan \theta . Here θ\theta is zero (0).
Therefore, tan[(2×3×π)+0]=tan0\tan \left[ {\left( {2 \times 3 \times {\pi }} \right) + {0^ \circ }} \right] = \tan {0^ \circ }
The value of tan0\tan {0^ \circ } is 0.
Therefore, the value of tan1080\tan {1080^ \circ } is 0.
So, the correct answer is “0”.

Note : Tan is the ratio of sine and cosine. So we can find the values of sin1080\sin {1080^ \circ } and cos1080\cos {1080^ \circ } ; and then divide them to get the value. Or we finally got that tan1080\tan {1080^ \circ } as tan0\tan {0^ \circ } , So we can divide sin0\sin {0^ \circ } by cos0\cos {0^ \circ } , to get its value.