Question
Mathematics Question on Trigonometric Functions
Find the value of sin(40∘+θ)cos(10∘+θ)−cos(40∘+θ)sin(10∘+θ).
A
1/2
B
1/4
C
1
D
0
Answer
1/2
Explanation
Solution
We have, sin(40∘+θ)⋅cos(10∘+θ)−cos(40∘+θ)⋅sin(10∘+θ) =sin\left\\{\left(40^{\circ}+\theta\right)-\left(10^{\circ}+\theta\right)\right\\} =sin30∘=21