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Question

Question: Find the value of \[\sec \dfrac{13{{\pi }^{c}}}{3}\]....

Find the value of sec13πc3\sec \dfrac{13{{\pi }^{c}}}{3}.

Explanation

Solution

In order to evaluate the value of sec13πc3\sec \dfrac{13{{\pi }^{c}}}{3}, we will be expressing 13πc3\dfrac{13{{\pi }^{c}}}{3} in such a way that we will be considering the principle angle to which 13πc3\dfrac{13{{\pi }^{c}}}{3} is nearer and then add the remaining angle measure so that it will be equal to the original angle given. And then we will be checking the quadrant it belongs to and decide if the value is positive or negative and then evaluate the value.

Complete step-by-step solution:
Let us have a brief regarding the trigonometric functions. The counter-clockwise angle between the initial arm and the terminal arm of an angle in standard position is called the principal angle. Its value is between 0{{0}^{\circ }} and 360{{360}^{\circ }}. The relationship between the angles and sides of a triangle are given by the trigonometric functions. The basic trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant. These are the basic main trigonometric functions used.
Now let us find the value of sec13πc3\sec \dfrac{13{{\pi }^{c}}}{3}.
We can express sec13πc3\sec \dfrac{13{{\pi }^{c}}}{3} as sec13π3=sec(4π+π3)\sec \dfrac{13\pi }{3}=\sec \left( 4\pi +\dfrac{\pi }{3} \right).
We get sec13π3=secπ3\sec \dfrac{13\pi }{3}=\sec \dfrac{\pi }{3} as 4π+θ4\pi +\theta will be in the first quadrant. Since it is in the first quadrant, sec(4π+θ)\sec \left( 4\pi +\theta \right) is positive.
\therefore The value of sec13πc3\sec \dfrac{13{{\pi }^{c}}}{3} is 22.

Note: In order to convert from radians to degrees, we have to multiply the radians by 180π{{180}^{\circ }}\pi radians. We use radians in trigonometry because they make it possible to relate a linear measure and an angle measure. The common error could be not converting the degree to radians or radians to degrees with accurate values or simply assuming the wrong values.