Question
Question: Find the value of m if \[\text{n(A)=2}\], \[\text{n(B)}\,\text{=}\,\text{m}\] and the number of rela...
Find the value of m if n(A)=2, n(B)=m and the number of relation from A to B is 64.
(a) 6
(b) 3
(c) 16
(d) 8
Solution
Hint: We know that the number of different relations from A to B is 2xy and number of relation from A to B is mentioned in the question as 64 and also number of elements of set B is given. Hence we will use these inputs to find the value of m.
Complete step-by-step answer:
Before proceeding with the question we must understand the concept of sets and relations.
A relation R from a non-empty set A to a non-empty set B is a subset of the cartesian product A !!×!! B. The subset is derived by describing the relationship between the first element and the second element of the ordered pairs in A !!×!! B.
If A has x elements and B has y elements, then A !!×!! B has x !!×!! y element. And the number of different relations from A to B is 2xy.
Number of given elements in set A and set B is mentioned in the question, so using this information we get,
Number of elements in set A: n(A)=2.......(1)
Number of elements in set B: n(B) = m.......(2)
And the number of relations from A to B is given in the question as 64 and the formula for the number of different relations from A to B is 2xy.
⇒2xy=64.......(3)
Here from equation (1) and equation (2) we get x as 2 and y as m and substituting these values in equation (3) we get,
⇒22m=64.......(4)
We know that 2 to the power 6 is 64, so changing 64 in terms of powers of 2 we get,
⇒22m=26.......(5)
As the base is 2 on both sides of equation (5) we equate the powers and then solve for m we get,