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Question

Question: Find the value of \(\log (\log i) = \) and choose the correct option: \({\text{A}}{\text{. log}...

Find the value of log(logi)=\log (\log i) = and choose the correct option:

A. logπ2{\text{A}}{\text{. log}}\dfrac{\pi }{2}
B. logiπ2{\text{B}}{\text{. logi}}\dfrac{\pi }{2}
C. logπ2+iπ2{\text{C}}{\text{. log}}\dfrac{\pi }{2} + \dfrac{{i\pi }}{2}
D. logπ2iπ2{\text{D}}{\text{. log}}\dfrac{\pi }{2} - \dfrac{{i\pi }}{2}

Explanation

Solution

Hint – We know, z=eiθ=cosθ+isinθz = {e^{i\theta }} = \cos \theta + i\sin \theta , where z is a complex number. Now, if there is no real part in a complex number then,
cosθ=0 θ=π2  \cos \theta = 0 \\\ \Rightarrow \theta = \dfrac{\pi }{2} \\\
Hence, we can say, if
z=i i=eiπ2  z = i \\\ \Rightarrow i = {e^{i\dfrac{\pi }{2}}} \\\
Use this to solve.

Complete step by step answer:
We have been asked to find log(logi)\log (\log i).
So, using the hint we can write, i=eiπ2i = {e^{i\dfrac{\pi }{2}}}.
So, the given equation log(logi)\log (\log i) will transform into-
log(logeiπ2)\log (\log {e^{i\dfrac{\pi }{2}}}).
Now, solving it further, we get-
log(logeiπ2)=log(i.π2) =log(iπ2)  \log (\log {e^{i\dfrac{\pi }{2}}}) = \log \left( {i.\dfrac{\pi }{2}} \right) \\\ = \log \left( {\dfrac{{i\pi }}{2}} \right) \\\
Hence, the value of log(logi)=log(iπ2)\log (\log i) = \log \left( {\dfrac{{i\pi }}{2}} \right).
Therefore, the correct option is B.

Note – Whenever solving such types of questions, always use the concepts of complex numbers to solve the question step by step. As mentioned in the solution, let z = I, since it does not have a real part so keep the cosθ=0\cos \theta = 0, from here we can find the value of theta as 90 degrees, and then our equation will be easier to solve.