Question

Find the value of:
(i) -4÷$\frac{2}{3}$
(ii) -$\frac{3}{5}$÷2
(iii) -$\frac{4}{5}$÷(-3)
(iv) -$\frac{1}{8}$÷$\frac{3}{4}$
(v) -$\frac{2}{13}$÷$\frac{1}{7}$
(vi) -$\frac{7}{12}$÷(-$\frac{2}{13}$)
(vii) $\frac{3}{13}$÷(-$\frac{4}{65}$)

Answer 1

(i)-4÷$\frac{2}{3}$
= -4×$\frac{3}{2}$
= -$\frac{12}{2}$
= -6

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(ii) -$\frac{3}{5}$÷2
= -$\frac{3}{5}$×$\frac{1}{2}$
= -$\frac{3}{10}$

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(iii) -$\frac{4}{5}$÷(-3)
= -$\frac{4}{5}$×$\frac{1}{-3}$
= (-4)×$\frac{1}{5}$×(-3)
= $\frac{-4}{-15}$
= $\frac{4}{15}$

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(iv) -$\frac{1}{8}$÷$\frac{3}{4}$
= -$\frac{1}{8}$×$\frac{4}{3}$
= -$\frac{4}{24}$
= -$\frac{1}{6}$

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(v) -$\frac{2}{13}$÷$\frac{1}{7}$
= -$\frac{2}{13}$×7
= -$\frac{14}{13}$

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(vi) -$\frac{7}{12}$÷(-$\frac{2}{13}$)
= -$\frac{7}{12}$×$\frac{13}{-2}$
= (-7)×$\frac{13}{12}$×(-2)
=$\frac{91}{24}$

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(vii) $\frac{3}{13}$÷(-$\frac{4}{65}$)
= $\frac{3}{13}$×$\frac{65}{-4}$
= 3×$\frac{65}{13}$×(-4)
= $\frac{195}{-52}$
= -$\frac{15}{4}$