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Question

Mathematics Question on Trigonometric Functions

Find the value of cos(29π/3)?\cos \,\,(29\pi /3)?

A

11

B

00

C

32\frac{\sqrt{3}}{2}

D

1/21/2

Answer

1/21/2

Explanation

Solution

cos(29π3)=cos((27+2)π3)\cos \left( 29\frac{\pi }{3} \right)=\cos \left( \frac{(27+2)\pi }{3} \right)
=cos(9π+2π3)=\cos \left( 9\pi +\frac{2\pi }{3} \right)
=cos2π3=cos(π2+π6)=sinπ6=12=-\cos \frac{2\pi }{3}=-\cos \left( \frac{\pi }{2}+\frac{\pi }{6} \right)=\sin \frac{\pi }{6}=\frac{1}{2}