Question
Mathematics Question on Trigonometric Functions
Find the value of cos(29π/3)?
A
1
B
0
C
23
D
1/2
Answer
1/2
Explanation
Solution
cos(293π)=cos(3(27+2)π)
=cos(9π+32π)
=−cos32π=−cos(2π+6π)=sin6π=21
Find the value of cos(29π/3)?
1
0
23
1/2
1/2
cos(293π)=cos(3(27+2)π)
=cos(9π+32π)
=−cos32π=−cos(2π+6π)=sin6π=21