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Question

Question: Find the value of \[2\sin 30^\circ + \cos 0^\circ + 3\sin 90^\circ \]....

Find the value of 2sin30+cos0+3sin902\sin 30^\circ + \cos 0^\circ + 3\sin 90^\circ .

Explanation

Solution

Here, we will first simplify the given equation using the sine value, sin30=12\sin 30^\circ = \dfrac{1}{2}, cosine value cos0=1\cos 0^\circ = 1, and sine value sin90=1\sin 90^\circ = 1 in the given expression to find the required value.

Complete step by step answer:

We are given that the equation is 2sin30+cos0+3sin902\sin 30^\circ + \cos 0^\circ + 3\sin 90^\circ .
We will now use the sine value, sin30=12\sin 30^\circ = \dfrac{1}{2} in the given equation, we get

2×12+cos0+3sin90 1+cos0+3sin90  \Rightarrow 2 \times \dfrac{1}{2} + \cos 0^\circ + 3\sin 90^\circ \\\ \Rightarrow 1 + \cos 0^\circ + 3\sin 90^\circ \\\

Using the cosine value, cos0=1\cos 0^\circ = 1 in the above equation, we get

1+1+3sin90 2+3sin90  \Rightarrow 1 + 1 + 3\sin 90^\circ \\\ \Rightarrow 2 + 3\sin 90^\circ \\\

Using the sine value, that is, sin90=1\sin 90^\circ = 1 in the above equation, we get

2+3×1 2+3 5  \Rightarrow 2 + 3 \times 1 \\\ \Rightarrow 2 + 3 \\\ \Rightarrow 5 \\\

Thus, the value of the given equation is 55.

Note: The key concept is to have good understanding of the basic trigonometric values and learn how to use the values from trigonometric tables. Students should have grasp of trigonometric values, for simplifying the given equation. The common mistake is students write cos0\cos 0^\circ equal to 0 instead of 1, which is a wrong. We will follow the BODMAS rule here, so do not add before multiplying or else the answer will be wrong.