Question
Question: Find the sum of the following arithmetic progression. \(50, 46, 42,....\) to \(10\) terms....
Find the sum of the following arithmetic progression.
50,46,42,.... to 10 terms.
Solution
Here, they have given an arithmetic series and they are asking to find the arithmetic progression. So, we have a formula to find the sum of n terms of an arithmetic progression that is given by: Sn=2n[2a+(n−1)d]. By using this formula we can get the required answer.
Complete Step by Step Solution:
In the given problem they have given an arithmetic progression, and asking us to find sum of the arithmetic progression.
In order to find the sum of n terms of an arithmetic progression we have a formula, given by
Sn=2n[2a+(n−1)d]
Where Sn is the sum of n terms.
n= number of terms.
a= first term of the given arithmetic progression.
d= common difference of the arithmetic progression.
The series is given by 50,46,42,.... to 10 terms.
From the given arithmetic progression, we can say that
Number of terms n=10
The first term of the given arithmetic progression i.e., a=50
Now, to find the common difference that is d, we follow the following procedure or formula
d=a2−a1Here, a1=50 and a2=46, by substituting these values, we get
d=45−50=−4
Now, by substituting the values of a,d and nin the sum of n terms of an arithmetic progression formula, we get
S10=210[2(50)+(10−1)(−4)]
On simplifying the above equation,
⇒S10=(5)[100+(9)(−4)]
⇒S10=(5)[100−36]
⇒S10=(5)[64]
⇒S10=320
Therefore the sum of the arithmetic progression that is 50,46,42,.... to 10 terms is 320.
Note:
If you want to cross verify the answer, or if you are not able to recall the formula then we can find the entire series, that is from the given expression 50,46,42,.... to 10 terms, we can notice that there is a difference of 4for every number so by using this difference first try to find the entire series then by adding these we can get the answer to cross verify.