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Question

Question: Find the sum of \[34 + 32 + 30 + ... + 10\]....

Find the sum of 34+32+30+...+1034 + 32 + 30 + ... + 10.

Explanation

Solution

In this question, we have to find out the sum from the given particular series.
We need to first find out the value of the first term and common difference. By subtracting the first term from the second term, we will get a common difference. Then put all the values in the formula of the nthn^{th} term of the sequence to find the nthn^{th} term of the sequence and then applying these to find out the sum of nthn^{th} partial sum of the arithmetic sequence, we can find out the required solution.
Formula:
Property of A.P.:
The nthn^{th} term of the Arithmetic sequence is
an=a+(n1)d{a_n} = a + \left( {n - 1} \right)d
The nthn^{th} partial sum of the Arithmetic sequence is
Sn=n2[2a+(n1)d]{S_n} = \dfrac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right]
Where,
a = first term of the sequence
d = common difference
n= number of terms

Complete step by step answer:
We need to find out the value of the sum 34+32+30+...+1034 + 32 + 30 + ... + 10.
a =first term of the sequence=3434.
d=the common difference=second term – first term=3432=234 - 32 = - 2.
Now we need to find out the value of n.
Since the difference between two consecutive numbers is the same, it is an arithmetic sequence.
We know that the nthn^{th} term of the arithmetic sequence is
an=a+(n1)d{a_n} = a + \left( {n - 1} \right)d
10=34+(n1)×210 = 34 + (n - 1) \times - 2
2(n1)=34102(n - 1) = 34 - 10
(n1)=242=12(n - 1) = \dfrac{{24}}{2} = 12
n=12+1=13n = 12 + 1 = 13
n = number of terms =1313.
The sum of 1313 th partial sum of the arithmetic sequence is
S13=132[2×34+(131)×(2)]{S_{13}} = \dfrac{{13}}{2}\left[ {2 \times 34 + \left( {13 - 1} \right) \times \left( { - 2} \right)} \right]
Or,S13=132[6812×2]{S_{13}} = \dfrac{{13}}{2}\left[ {68 - 12 \times 2} \right]
Or, S13=132×[6824]{S_{13}} = \dfrac{{13}}{2} \times \left[ {68 - 24} \right]
Or,S13=13×442{S_{13}} = 13 \times \dfrac{{44}}{2}
Or,S13=13×22=286{S_{13}} = 13 \times 22 = 286
Hence, 34+32+30+...+1034 + 32 + 30 + ... + 10=286286.

Note: An arithmetic progression is a sequence of numbers for which if we take the difference between any two successive numbers, we will get a constant.
In general, we write an Arithmetic sequence like this: \left\\{ {a,a + d,a + 2d,a + 3d....} \right\\} where a is the first term and d is the difference between the terms, called the common difference.