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Chemistry Question on coordination compounds

Find the spin magnetic moment ratio for complexes [Cr(Cn)6]−3[Cr(Cn)_{6}]^{-3} & [Cr(H2O)6]+3[Cr(H_{2}O)_{6}]^{+3}

Answer

The correct answer is 1:1
Spin only magnet magnetic for [Cr(CN)6]−3(d3)[Cr(CN)_6]^{-3} (d^3) =15= \sqrt{15} B.M.
For [Cr(H2O)6]+3(d3)=15[Cr(H_2O)_6]^{+3} (d^3) = \sqrt{15} B.M.
∴\therefore the ratio is 1:1