Question

Find the smallest number that is divisible by each of 8, 9, and 10.

Answer 1

The smallest number divisible by multiple numbers is their LCM. Calculate:
$Prime Factorizations: 8 = 2^3, \, 9 = 3^2, \, 10 = 2 \cdot 5$
$LCM = 2^3 \cdot 3^2 \cdot 5 = 360$
Thus, the smallest number divisible by 8, 9, and 10 is 360.