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Question: Find the slope of the line and its intercept using the following equation of line: \(y = 0.5x\)...

Find the slope of the line and its intercept using the following equation of line: y=0.5xy = 0.5x

Explanation

Solution

find the slope of a line when an equation of line is given in the question we must use the slope intercept form of a linear equation. In the slope intercept form of the line equation, the coefficient of xx is slope mm and the constant term with its proper sign is yintercept (c)y - {\text{intercept (c)}}

Complete step by step solution:
Firstly we write the given equationy=0.5x - - - - - - - - - (i)y = 0.5x{\text{ - - - - - - - - - (i)}}
Simplifying the equation we have -
y=12xy = \dfrac{1}{2}x
As we know the equation of a line is given by-
y  =  mx+cy\; = \;mx + c
Where  m  =  slope  of  line\;m\; = \;{\text{slope}}\;{\text{of}}\;{\text{line}}and c=y - intercept  of  linec = {\text{y - intercept}}\;{\text{of}}\;{\text{line}}
Comparing this standard equation with equation (i) we get slope –
m=12  and  c=0m = \dfrac{1}{2}\;{\text{and}}\;c = 0
Here we get the desired result and the value of c=0c = 0 shows that the line passes through the origin.

Note: Slope of a line can be understood, in layman terms, as rise over run in a Cartesian coordinate system. In this there are two axes namely xaxis  and  yaxisx - axis\;{\text{and}}\;y - axis more precisely; Slope of a line is the change in the values of yy with respect to the change in values of xx. It is denoted as mm which is a debatable notation for it because it is not clear why it is represented with mm

Here the slope will be the ratio of value of yaxis  and  xaxisy - axis\;{\text{and}}\;x - axis meaning it characterizes the direction of line. By the figure itself, we can see that while finding a slope when two point of a line are given we simply divide the difference of the yy coordinates of the 2 points by the difference of the xx coordinates of the two same points i.e.
Two points of a line a given as(x1,y1)  and  (x2,y2)({x_{1,}}{y_1})\;{\text{and}}\;({x_{2,}}{y_2})then we calculate the slope as- m  =  (y2y1)(x2x1)m\; = \;\dfrac{{({y_2} - {y_1})}}{{({x_2} - {x_1})}}