Question

Find the second order derivatives of the function
$x^2+3x+2$

Answer 1

The correct answer is 2
Let $y=x^2+3x+2$
Then,
$\frac{dy}{dx}=\frac{d}{dx}(x^2)+\frac{d}{dx}(3x)+\frac{d}{dx}(2)=2x+3+0=2x+3$
$∴\frac{d^2y}{dx^2}=\frac{d}{dx}(2x+3)=\frac{d}{dx}(2x)+\frac{d}{dx}(3)=2+0=2$