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Question: Find the ratio in which the line segment joining the points \(\left( 1,2 \right)\) and \(\left( -2,3...

Find the ratio in which the line segment joining the points (1,2)\left( 1,2 \right) and (2,3)\left( -2,3 \right) is divided by the line 3x+4y=73x+4y=7.

Explanation

Solution

Hint: Find the equation of line passing through given points. Then find the intersections point. For line equation through (a,b)(c,d)\left( a,b \right)\left( c,d \right) we have formula:
(yb)=(db)(ca)(xa)\left( y-b \right)=\dfrac{\left( d-b \right)}{\left( c-a \right)}\left( x-a \right)
Use this to find an equation. Substitute the y in terms of x into other equations. Solve for x. Place the value of x back for the value of y. Now take ratio to be m:1mm:1-m. By formula, if (x,y)\left( x,y \right) divides (a,b);(c,d)\left( a,b \right);\left( c,d \right) by ratio m:(1m)m:\left( 1-m \right) then:
y=m(d)+(1m)by=m\left( d \right)+\left( 1-m \right)b
By using this find m.

Complete step-by-step answer:
Find the equation through given points in the question. Let point is given by the coordinates of the value A(1,2)A\left( 1,2 \right) . Let point B is given by the coordinate of the value B(2,3)B\left( -2,3 \right).
Line equation passing through (a,b);(c,d)\left( a,b \right);\left( c,d \right) is given by the formula:
(yb)=(db)(ca)(xa)\left( y-b \right)=\dfrac{\left( d-b \right)}{\left( c-a \right)}\left( x-a \right)
Here, a=1, b=2, c=-2, d=3a=1,\text{ b=2, c=-2, d=3}
By substituting this values in the given formula, we get
(y2)=(32)(21)(x1)\left( y-2 \right)=\dfrac{\left( 3-2 \right)}{\left( -2-1 \right)}\left( x-1 \right)
So, by cross multiplying the terms the equation, we get:
3y+6=x1-3y+6=x-1
By adding 3y term on both sides of the equation, we get:
6=x+3y16=x+3y-1
By adding 1 on both sides of the equation, we get:
x+3y=7x+3y=7
By substituting the value of x in the 2nd line equation. Given in question 2nd line equation is given by equation:
3x+4y=73x+4y=7 , we get:
3(73y)+4y=73\left( 7-3y \right)+4y=7
By simplifying, we get value of y to be 145\dfrac{14}{5}
By value of y, we get the value of x to be 75-\dfrac{7}{5} .
Let point P(75,145)P\left( -\dfrac{7}{5},\dfrac{14}{5} \right) divide line in ratio m:1mm:1-m .
By basic knowledge of coordinate geometry, we can say:
145=m×3+(1m)2=3m+22m\dfrac{14}{5}=m\times 3+\left( 1-m \right)\cdot 2=3m+2-2m
By simplifying we get the value of m to be 45\dfrac{4}{5}
Ratio =m:1m=45:15=4:1=m:1-m=\dfrac{4}{5}:\dfrac{1}{5}=4:1
So, the required ratio is 4:14:1

Note: Apply coordinate geometry properly. The required ratio is not m it is m:1mm:1-m don’t forget to apply this or else you will get 4:5.
Alternate method:
Instead of using section formulas you can use the distance formula. Find the distance between the intersection point and given 2 points. Then take the ratio of 2 distances to get the required result.
Distance between 2 points (a, b) and (c, d) is given by:
Distance=(ac)2+(bd)2\text{Distance}=\sqrt{{{\left( a-c \right)}^{2}}+{{\left( b-d \right)}^{2}}}