Question
Question: Find the ratio in which the line segment joining the points A (3, -3) and B (-2, 7) is divided by th...
Find the ratio in which the line segment joining the points A (3, -3) and B (-2, 7) is divided by the x-axis. Two times the x-coordinate of the point of division is
Solution
Hint: In this question, the concept is that any coordinate on the x axis is (x, 0). Then use the section formula to calculate the ratio and the x-coordinate of the point of division.
Complete step-by-step answer:
Let us suppose that the line segment joining the points A and B is divided by the x-axis in the ratio (m : n) as shown in figure.
So C is the point which lies on the x-axis.
Now as we know that on x-axis the coordinate of y is zero.
Therefore (y3 = 0)
So the coordinates of C = (x3, 0)
Now let A = (x1, y1) = (3, -3)
And B = (x2, y2) = (-2, 7)
So according to section formula the coordinates of C is written as
x3=m+nm.x2+n.x1,y3=m+nm.y2+n.y1
Now substitute all the values in this equation we have,
x3=m+nm(−2)+3n..........(1)
And
0=m+n7m+n(−3)...........(2)
Now simplify first equation (2) we have,
0(m+n)=7m+n(−3)
⇒7m−3n=0
⇒7m=3n......................... (3)
⇒nm=73
So this is the required ratio in which the line segment joining the points A and B divides by x-axis.
Now from equation (1) we have,
x3=m+n−2m+3n
From equation (3) we have,
x3=m+37m−2m+7m=10m15m=23
So the coordinates of the x-axis is (23,0)
Now we have to calculate the two times the x-coordinate of the point of division.
So simply multiply by 2 in the x-coordinate.
Therefore two times the x-coordinate of the point of division is (3, 0).
So this is the required answer.
Note: In this question firstly we have founded out the ratio in which the line segment is divided by the x-axis. Using this ratio we are able to find the x coordinate of the point on x-axis which is dividing the line segment. Twice the x coordinate can easily be found by simply multiplying the x coordinate with two.