Question
Question: Find the ratio in which \[P\left( {4,m} \right)\] divides the line segment joining the points \[A\le...
Find the ratio in which P(4,m) divides the line segment joining the points A(2,3) and B(6,−3). Hence find ‘m'.
Solution
Hint : To solve this problem we will start with applying the section formula, by assuming the point P(4,m) is dividing the line segment joining A(2,3) and B(6,−3) in the ratio k:1. Then, after getting the value of k, we will use to find the value of m.
Complete step-by-step answer :
We need to find the ratio in which P(4,m) divides the line segment joining the points A(2,3) and B(6,−3), and also we need to find the value of ‘m'. We will use the section formula here, because here a point P(x,y) is dividing the line segment joining A(x1,y1) and B(x2,y2) in the ratio m:n.
The general formula of section formula is mentioned below.
⇒(x,y)=(m+nmx1+nx2,m+nmy1+ny2)
Here, let the point P(4,m) is dividing the line segment joining A(2,3) and B(6,−3) in the ratio k:1. So, on applying the values in the above formula, we get
⇒P(4,m)=(k+1k(6)+1(2),k+1k(−3)+1(3))
⇒4=k+16k+2
So, the ratio in which P(4,m) divides the line segment joining the points A(2,3) and B(6,−3)is 1:1.
Now, after applying the value of k, we get
⇒m=1+1−3(1)+3(1)
⇒m=0
So, the value of m is 0.
Thus, the ratio in which P(4,m) divides the line segment joining the points A(2,3) and B(6,−3)is 1:1 and the value of m is 0.
Note : In the solutions, we have applied the section formula. Let us understand in detail.
The coordinates of the point P(x,y) which divides the line segment joining the points A(x1,y1) and B(x2,y2) in ratio of m:n are
(m+nmx1+nx2,m+nmy1+ny2).
This formula is called section formula. This formula tells us about the coordinates of the point which divides a given line segment into two parts such that their lengths are in the ratio m:n.