Solveeit Logo

Question

Question: Find the ratio in which \[P\left( {4,m} \right)\] divides the line segment joining the points \[A\le...

Find the ratio in which P(4,m)P\left( {4,m} \right) divides the line segment joining the points A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right). Hence find ‘m'.

Explanation

Solution

Hint : To solve this problem we will start with applying the section formula, by assuming the point P(4,m)P\left( {4,m} \right) is dividing the line segment joining A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right) in the ratio k:1.k:1. Then, after getting the value of k, we will use to find the value of m.

Complete step-by-step answer :
We need to find the ratio in which P(4,m)P\left( {4,m} \right) divides the line segment joining the points A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right), and also we need to find the value of ‘m'. We will use the section formula here, because here a point P(x,y)P\left( {x,y} \right) is dividing the line segment joining A(x1,y1)A\left( {{x_1},{y_1}} \right) and B(x2,y2)B\left( {{x_2},{y_2}} \right) in the ratio m:n.
The general formula of section formula is mentioned below.
(x,y)=(mx1+nx2m+n,my1+ny2m+n)\Rightarrow \left( {x,y} \right) = \left( {\dfrac{{m{x_1} + n{x_2}}}{{m + n}},\dfrac{{m{y_1} + n{y_2}}}{{m + n}}} \right)
Here, let the point P(4,m)P\left( {4,m} \right) is dividing the line segment joining A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right) in the ratio k:1.k:1. So, on applying the values in the above formula, we get
P(4,m)=(k(6)+1(2)k+1,k(3)+1(3)k+1)\Rightarrow P\left( {4,m} \right) = \left( {\dfrac{{k(6) + 1(2)}}{{k + 1}},\dfrac{{k( - 3) + 1(3)}}{{k + 1}}} \right)
4=6k+2k+1\Rightarrow 4 = \dfrac{{6k + 2}}{{k + 1}}

4k+4=6k+2 2k=2 k=1  \Rightarrow 4k + 4 = 6k + 2 \\\ \Rightarrow 2k = 2 \\\ \Rightarrow k = 1 \\\

So, the ratio in which P(4,m)P\left( {4,m} \right) divides the line segment joining the points A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right)is 1:1.1:1.
Now, after applying the value of k, we get
m=3(1)+3(1)1+1\Rightarrow m = \dfrac{{ - 3(1) + 3(1)}}{{1 + 1}}
m=0\Rightarrow m = 0
So, the value of m is 0.0.
Thus, the ratio in which P(4,m)P\left( {4,m} \right) divides the line segment joining the points A(2,3)A\left( {2,3} \right) and B(6,3)B\left( {6, - 3} \right)is 1:11:1 and the value of m is 0.0.

Note : In the solutions, we have applied the section formula. Let us understand in detail.
The coordinates of the point P(x,y) which divides the line segment joining the points A(x1,y1)A\left( {{x_1},{y_1}} \right) and B(x2,y2)B\left( {{x_2},{y_2}} \right) in ratio of m:n are
(mx1+nx2m+n,my1+ny2m+n)\left( {\dfrac{{m{x_1} + n{x_2}}}{{m + n}},\dfrac{{m{y_1} + n{y_2}}}{{m + n}}} \right)..
This formula is called section formula. This formula tells us about the coordinates of the point which divides a given line segment into two parts such that their lengths are in the ratio m:n.