Solveeit Logo

Question

Question: Find the rate of change of the area of a circle with respect to its radius \(r\) when \(r = 3cm\) an...

Find the rate of change of the area of a circle with respect to its radius rr when r=3cmr = 3cm and r=4cmr = 4cm.

Explanation

Solution

Let the radius of the circle be r and the area of the circle be A.
We must calculate dAdr\dfrac{{dA}}{{dr}} to determine the rate of change of Area concerning Radius.
Area of Circle A=πr2A = \pi {r^2} is a well-known formula.

Complete step-by-step solution:
Let r denote the radius of the circle and AA denotes the area of the circle.
The area of a circle (AA) with radius (rr) is calculated as follows:
A=πr2A = \pi {r^2}
The area's rate of change concerning its radius is now given by,
dAdr=d(πr2)dr\dfrac{{dA}}{{dr}} = \dfrac{{d\left( {\pi {r^2}} \right)}}{{dr}} (we will go step by step derivation as follows)
dAdr  =  πd(r2)dr\dfrac{{dA}}{{dr}}\; = \;\pi \dfrac{{d\left( {{r^2}} \right)}}{{dr}} (taking out the constant term pie)
dAdr=π(2r)\dfrac{{dA}}{{dr}} = \pi \left( {2r} \right) (differentiate concerning r)
dAdr=2πr\dfrac{{dA}}{{dr}} = 2\pi r
When r=3cmr = 3cm
We have, dAdr=2πr\dfrac{{dA}}{{dr}} = 2\pi r
Putting r=3cmr = 3cm
dAdrr  =  3=2π×3{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;3}} = 2\pi \times 3
dAdrr  =  3=6π{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;3}} = 6\pi
Since the area is measured in centimeters squared (cm2)({\text{c}}{{\text{m}}^2}) and the radius is measured in centimeters (cm)({\text{cm}}),
dAdrr  =  3=6π  cm2/cm{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;3}} = 6\pi \;{\text{c}}{{\text{m}}^2}/cm
As a result, when r=3cmr = 3cm, Area increases at a rate of 6π  cm2/cm6\pi \;{\text{c}}{{\text{m}}^2}/cm.
When r=4cmr = 4cm
We have, dAdr=2πr\dfrac{{dA}}{{dr}} = 2\pi r
Putting r=4cmr = 4cm
dAdrr  =  4=2π×4{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;4}} = 2\pi \times 4
dAdrr  =  4=8π{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;4}} = 8\pi (which is the required rate of change of the area of the circle)
Since the area is measured in centimeters squared (cm2)({\text{c}}{{\text{m}}^2}) and the radius is measured in centimeters (cm)({\text{cm}}),
dAdrr  =  4=8π  cm2/cm{\left. {\dfrac{{dA}}{{dr}}} \right|_{r\; = \;4}} = 8\pi \;{\text{c}}{{\text{m}}^2}/cm
As a result, when r=4cmr = 4cm, Area increases at a rate of 8π  cm2/cm8\pi \;{\text{c}}{{\text{m}}^2}/cm.
Hence, when the radius of the circle is 3cm3cm, the area of the circle changes at a rate of 6π  cm2/cm6\pi \;{\text{c}}{{\text{m}}^2}/cm , and when the radius of the circle is 4cm4cm, the area of the circle changes at a rate of 8π  cm2/cm8\pi \;{\text{c}}{{\text{m}}^2}/cm.

Note: We must calculate dAdr\dfrac{{dA}}{{dr}} to determine the rate of change of Area concerning Radius. Since the area is measured in centimeters squared (cm2)({\text{c}}{{\text{m}}^2}). The radius is measured in centimeters (cm)({\text{cm}}), the unit for rate of change of area w.r.t radius of a circle is cm2/cm{\text{c}}{{\text{m}}^2}/cm.