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Question

Chemistry Question on Rate of a Chemical Reaction

Find the rate constant for first order gaseous reaction:
A(g)−−−−−−−>B(g)+C(g)A(g)-------> B(g) + C(g)

A

K=2.303tlog⁡pi2pi−ptK = \frac{2.303}{t} \log \frac{p_i}{2p_i-p_t}

B

K=2.303t log2pipi−ptK =\frac{ 2.303}{t}\ log \frac{2p_i}{p_i-p_t}

C

K=2.303tlog⁡pi−pt2piK = \frac{2.303}{t} \log \frac{p_i-p_t}{2p_i}

D

K=2.303tlog⁡2pt2pi−ptK = \frac{2.303}{t} \log \frac{2p_t}{2p_i-p_t}

Answer

K=2.303tlog⁡pi2pi−ptK = \frac{2.303}{t} \log \frac{p_i}{2p_i-p_t}

Explanation

Solution

The Correct Option is (A) : K=2.303tlog⁡pi2pi−ptK = \frac{2.303}{t} \log \frac{p_i}{2p_i-p_t}