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Question: Find the range of the function \[f(x) = 2 - 3x\], \[x \in R\], \[x > 0\]....

Find the range of the function f(x)=23xf(x) = 2 - 3x, xRx \in R, x>0x > 0.

Explanation

Solution

The range of a function f(x)f(x) refers to the possible values that a function can attain for the values of xx which are in the domain of f(x)f\left( x \right).

Complete step by step solution:
The domain of a function f(x)f(x) refers to the set of values of xx for which f(x)f\left( x \right) is defined. It is given that f(x)f\left( x \right) is defined for all x>0x > 0. Hence the domain of f(x)f\left( x \right) is (0,)\left( {0,\infty } \right).
To find the range of a function we need to find the values of f(x)f(x) for all xx belonging to the domain of xx.
Given:
x>0x > 0
We need to transform the xx on the left hand side to 23x2 - 3x, for that multiply both sides by 33:
3x>0\Rightarrow 3x > 0
Multiply both sides by - sign:
3x<0\Rightarrow - 3x < 0
Note that the sign changed from > to < as we multiplied by - on both sides.
Add 22 to both sides:
23x<2\Rightarrow 2 - 3x < 2

Therefore the range of f(x)f\left( x \right) is (,2)( - \infty ,2).

Note:
For solving any problems like this where the domain and range needs to be found, first the definition of the given function needs to be understood. First the domain of the function must be found following the definition then the range can be easily found accordingly. For example if a function is like f(x)=4xf(x) = \sqrt {4 - x} , then by the definition of roots any number under root will always be positive. So for the domain 4x4 - x must always be greater than 00 . In this way the definitions of various functions need to be analysed.