Solveeit Logo

Question

Mathematics Question on Relations and functions

Find the range of each of the following functions.
(i) f(x) = 2 - 3x, x ∈ R, x> 0.
(ii) f(x) = x2+ 2, x, is a real number.
(iii) f(x) = x, x is a real number

Answer

(i) f(x) = 2 -3x, x ∈ R, x> 0
The values of f(x) for various values of real numbers x> 0 can be written in the tabular form as

x0.010.10.9122.545...
f(x)1.971.7-0.7-1-4-5.5-10-13...

Thus, it can be clearly observed that the range of fis the set of all real numbers less than 2.
i.e., range of f= (-, 2)
Alter:
Let x > 0
⇒3x > 0
⇒ 2-3x< 2
⇒ f(x) < 2
∴Range of f = (-, 2)
(ii) f(x) = x2+ 2, x, is a real number
The values of f(x) for various values of real numbers xcan be written in the tabular form as

x0±0.3±0.8±1±2±3..…
f(x)22.092.643611..…

Thus, it can be clearly observed that the range of fis the set of all real numbers greater than 2.
i.e., range of f= [2, ∞)
Alter:
Let x be any real number.
Accordingly,
x2 ≥0
⇒ x2+ 2 ≥0 + 2
⇒ x2+ 2 ≥2
⇒ f(x) ≥2
∴ Range of f = [2, )
(iii) f(x) = x, x is a real number
It is clear that the range of fis the set of all real numbers.
∴ Range of f = R