Question

Find the product:
(i)$\frac{9}{2}$×(-$\frac{7}{4}$)
(ii) $\frac{3}{10}$×(-9)
(iii) -$\frac{6}{5}$×$\frac{9}{11}$
(iv) $\frac{3}{7}$×(-$\frac{2}{5}$)
(v) $\frac{3}{11}$×$\frac{2}{5}$
(vi) $\frac{3}{-5}$ ×$\frac{-5}{3}$

Answer 1

(i) $\frac{9}{2}$×(-$\frac{7}{4}$)
= $\frac{9×(-7)}{2×4}$ = -$\frac{63}{8}$

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(ii) $\frac{3}{10}$×(-9)
= $(\frac{3}{10}) ×\frac{-9}{1}$ = $\frac{3×(-9)}{10×1}$= $\frac{-27}{10}$

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(iii) -$\frac{6}{5}$×$\frac{9}{11}$
= $\frac{-6×9}{5×11}$ = -$\frac{54}{55}$

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(iv)$\frac{3}{7}$×(-$\frac{2}{5}$)
= $\frac{3×(-2)}{7×5}$ = $-\frac{6}{35}$

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(v) $\frac{3}{11}$×$\frac{2}{5}$
= $\frac{3×2}{11×5}$= $\frac{6}{55}$

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(vi) $\frac{3}{-5}$ ×$\frac{-5}{3}$
= $\frac{3×(-5)}{(-5)×3}$ = $\frac{-15}{-15}$= 1