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Question: Find the product .\[C{{H}_{3}}-C{{H}_{2}}-OH\xrightarrow{HI}?\]...

Find the product .CH3−CH2−OH→HI?C{{H}_{3}}-C{{H}_{2}}-OH\xrightarrow{HI}?

Explanation

Solution

When the alcohols are treated with HBr, HCl they undergo nucleophilic substitution reaction. The primary alcohol undergoes theSN2S{{N}_{2}}mechanism. The HI are most reactive towards alcohol because they have large bond length. It easily gets dissociated into its respective ions. They also have low bond dissociation energy. Due to which the HI performs nucleophilic substitution reactions.

Complete step by step answer:
At the point when treated with HBr or HCl or HI alcohols regularly go through a nucleophilic replacement response to produce an alkyl halide and water. Alcohol relative reactivity request: 3∘>2∘>1∘>methyl3 ^\circ > 2 ^\circ > 1 ^\circ > methyl. Hydrogen halide reactivity request: HI > HBr > HCl > HF (resembling acidity request).
Hydrogen iodide (HI) is a diatomic atom and hydrogen halide. Watery arrangements of HI are known as hydroiodic corrosive or hydriodic corrosive, a solid corrosive. Hydrogen iodide and hydroiodic corrosive are, nonetheless, unique in that the previous is a gas under standard conditions, though the other is a watery arrangement of said gas. They are interconvertible. HI is utilized in natural and inorganic union as one of the essential wellsprings of iodine and as a decreasing specialist.
HI is favoured over other hydrogen halides on the grounds that the iodide particle is a greatly improved nucleophile than bromide or chloride, so the response can happen at a sensible rate absent really any warming. This response additionally happens for auxiliary and tertiary alcohols, yet replacement happens through the SN1 pathway.
HI (or HBr) can likewise be utilized to sever ethers into alkyl iodides and alcohols, in a response like the replacement of alcohols. This sort of cleavage is critical in light of the fact that it tends to be utilized to change over a synthetically stable and inactive ether into more receptive species
CH3−CH2−OH→HICH3−CH2−I+H2OC{{H}_{3}}-C{{H}_{2}}-OH\xrightarrow{HI}C{{H}_{3}}-C{{H}_{2}}-I+{{H}_{2}}O

Note: The tertiary alcohols are more readily perform the reaction with alkyl halides because of more number of alkyl groups. This is due to +I effect present in it. The tertiary alkyl compound will follow SN1S{{N}_{1}}reaction and form the alkyl halide. The alkyl halides are reactive because of their bonds between carbon and halogens. There is a large difference between carbon and hydrogen. The bond formed is a highly polarized covalent bond.