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Question

Mathematics Question on Inverse Trigonometric Functions

Find the principal value of tan-1(3)\bigg(-\sqrt3\bigg)

Answer

Let tan-1(3)=y\big(-\sqrt3\big)=y
Then ,tany=3=tan(π3)=tan(π3)tan \,y = -\sqrt3=-tan\Big(\frac {\pi}{3}\Big)=tan \Big(\frac{-\pi}{3}\Big)
We know that the range of the principal value branch of tan-1 is
(π2,π2)andtan(π3)is3.\bigg(\frac {-\pi}{2},\frac {\pi}{2}\bigg) and\, tan \bigg(\frac{-\pi}{3}\bigg)is \,-\sqrt3.
Therefore, the principal value of tan-1(3)(-\sqrt3) is π3-\frac{\pi}{3}