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Question

Mathematics Question on Inverse Trigonometric Functions

Find the principal value of cos-1(32)\bigg(\frac {\sqrt3} {2}\bigg)

Answer

Let cos-1(32)=y\bigg(\frac {\sqrt3}{2}\bigg)=y
Then, cosy=32=cos(π6)cos \,y= \frac {\sqrt3}{2}= cos \bigg(\frac{\pi}{6}\bigg)
We know that the range of the principal value branch of cos-1 is
[0,π] and cos π6=32\frac{\pi}{6}=\frac{\sqrt3}{2}

Therefore, the principal value of cos-1 (32)isπ6\bigg(\frac{\sqrt3}{2}\bigg) is \, \frac {\pi}{6}