Question
Question: Find the power delivered by the sources in the circuit shown in figure: .
Complete step by step answer:
Let’s start by applying Kirchhoff’s voltage law in the loop ‘a b c d’, starting from the point a and moving in the direction of the current.
At first we encounter a voltage source of 20-volt but it is in the opposite direction to the flow of current so, as per the sign convention we get a decrease of 20-volt (-20 V). Then a resistor of 2 ohm, which decreases the potential by 2i. A 50-volt voltage source increases the potential followed by the decrease of potential by i. Thus, we reach the point ‘a’ from where we started.
By Kirchhoff’s voltage law
−20−2i+50−i=0
⇒30−3i=0
⇒30=3i
⇒i=10
Since we know the current, we can find the value of power dissipated by the formula (P=i2R)
Total power:
P=102×2+102×1
⇒P=200+100
∴P=300W
Thus, the total power dissipated is 300 watts.
Note: There is also a direct way to solve this problem for competitive exams.First, we find the total equivalent voltage of the circuit which is 30-volt as the two sources are align against each other, but the resistance gets added simply and these two are in series with each other, so total resistance becomes 3 ohms. Thus, we can find the current and solve this problem.