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Question: Find the period of the function \(\sin \left( {3x} \right)\)....

Find the period of the function sin(3x)\sin \left( {3x} \right).

Explanation

Solution

We know that for a function represented as y=Asin(Bx+C)  and  y=Acos(Bx+C)y = A\sin \left( {Bx + C} \right)\;{\text{and}}\;y = A\cos \left( {Bx + C} \right)the period is given by 2πB\dfrac{{2\pi }}{B} radians. So the function sin(3x)\sin \left( {3x} \right) has to be converted into the above form. Also by converting it we can then find the period directly.

Complete step by step solution:
Given, sin(3x)............................(i)\sin \left( {3x} \right)............................\left( i \right)
We know that a periodic function is a function which repeats its values on regular intervals or periods. Also a function ffis said to be periodic with a period nn if it follows the following condition:
f(a+n)=f(a)        n>0f\left( {a + n} \right) = f\left( a \right)\;\;\forall \;\;n > 0
Also for a function which can be represented as y=Asin(Bx+C)  and  y=Acos(Bx+C)y = A\sin \left( {Bx + C} \right)\;{\text{and}}\;y = A\cos \left( {Bx + C} \right) the period is given by 2πB\dfrac{{2\pi }}{B} radians.
Now our given function is sin(3x)\sin \left( {3x} \right) which has to represent in the formy=Asin(Bx+C)y = A\sin \left( {Bx + C} \right).

Now we know that in the Cartesian system the trigonometric function sine is positive in Quadrant I and Quadrant IV. So we can rewrite sin(3x)\sin \left( {3x} \right) as below:
sin(3x)=sin(3x+2π).........................(ii)\sin \left( {3x} \right) = \sin \left( {3x + 2\pi } \right).........................\left( {ii} \right)
Now we have the general equation y=Asin(Bx+C)y = A\sin \left( {Bx + C} \right).
So on comparing it with (ii) we can write that:
B=3    and    C=2πB = 3\;\;{\text{and}}\;\;C = 2\pi

Also from the general equation the period of the function is given by: 2πB\dfrac{{2\pi }}{B} radians
Also here we have found that the value ofB  is  3B\;{\text{is}}\;3. Therefore the period of the function sin(3x)\sin \left( {3x} \right) would be 2π3\dfrac{{2\pi }}{3} radians.It simply implies that the arc would be rotating 3 times after which the function sin(3x)\sin \left( {3x} \right) would come back to its initial value again.

Note: Here y=Asin(Bx+C)  and  y=Acos(Bx+C)y = A\sin \left( {Bx + C} \right)\;{\text{and}}\;y = A\cos \left( {Bx + C} \right) are the basic representations of sine and cosine functions respectively. Also we know that frequency and period are inverse to each other or in order to find the frequency of a function we just have to find the reciprocal of the period of the function.