Question
Question: Find the period of the function \(\sin \left( {3x} \right)\)....
Find the period of the function sin(3x).
Solution
We know that for a function represented as y=Asin(Bx+C)andy=Acos(Bx+C)the period is given by B2π radians. So the function sin(3x) has to be converted into the above form. Also by converting it we can then find the period directly.
Complete step by step solution:
Given, sin(3x)............................(i)
We know that a periodic function is a function which repeats its values on regular intervals or periods. Also a function fis said to be periodic with a period n if it follows the following condition:
f(a+n)=f(a)∀n>0
Also for a function which can be represented as y=Asin(Bx+C)andy=Acos(Bx+C) the period is given by B2π radians.
Now our given function is sin(3x) which has to represent in the formy=Asin(Bx+C).
Now we know that in the Cartesian system the trigonometric function sine is positive in Quadrant I and Quadrant IV. So we can rewrite sin(3x) as below:
sin(3x)=sin(3x+2π).........................(ii)
Now we have the general equation y=Asin(Bx+C).
So on comparing it with (ii) we can write that:
B=3andC=2π
Also from the general equation the period of the function is given by: B2π radians
Also here we have found that the value ofBis3. Therefore the period of the function sin(3x) would be 32π radians.It simply implies that the arc would be rotating 3 times after which the function sin(3x) would come back to its initial value again.
Note: Here y=Asin(Bx+C)andy=Acos(Bx+C) are the basic representations of sine and cosine functions respectively. Also we know that frequency and period are inverse to each other or in order to find the frequency of a function we just have to find the reciprocal of the period of the function.