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Question: Find the percentage of nitrogen in an organic compound analysed by Kjeldahl method \(1.61\) g of the...

Find the percentage of nitrogen in an organic compound analysed by Kjeldahl method 1.611.61 g of the compound produced NH3{\rm{N}}{{\rm{H}}_{\rm{3}}} which was absorbed in 250  mL{\rm{250}}\;{\rm{mL}} of N2  H2SO4\dfrac{{\rm{N}}}{{\rm{2}}}\;{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} solution. The remaining acid was then diluted to one litre, 25  mL{\rm{25}}\;{\rm{mL}} of which required 25.5  mL{\rm{25}}{\rm{.5}}\;{\rm{mL}} of N/10{\rm{N/10}} NaOH for exact neutralization.

Explanation

Solution

: We know that the Kjeldahl method is generally used for the determination of nitrogen percentage in any given organic compound by several chemical equations. The volumes of acid and base are needed for the Kjeldahl method.

Complete answer:
The given mass of the organic compound is 1.61  g{\rm{1}}{\rm{.61}}\;{\rm{g}}.
The given volume of sulfuric acid is 250  mL{\rm{250}}\;{\rm{mL}}.
The given volume of sodium hydroxide solution is 25.5  mL{\rm{25}}{\rm{.5}}\;{\rm{mL}}.
Now, let us first calculate the percentage of nitrogen by Kjeldahl’s method by using the formula as shown below.
%  of  N2  by  Kjeldlals  method=1.4×M×2×(VV12)Mass  of  organic  compound{\rm{\% }}\;{\rm{of}}\;{{\rm{N}}_{\rm{2}}}\;{\rm{by}}\;{\rm{Kjeldlal's}}\;{\rm{method}} = \dfrac{{1.4 \times M \times 2 \times \left( {\dfrac{{V - {V_1}}}{2}} \right)}}{{{\rm{Mass}}\;{\rm{of}}\;{\rm{organic}}\;{\rm{compound}}}}
Where,
MM is the molarity of the substance.
VV is the volume of sulfuric acid.
V1{V_1} is the volume of sodium hydroxide solution.
The value of N2  H2SO4=M4  H2SO4\dfrac{{\rm{N}}}{{\rm{2}}}\;{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} = \dfrac{{\rm{M}}}{4}\;{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} which means n=2{\rm{n}} = 2.
Substitute the respective values in the above equation. We get,
%  of  N2  by  Kjeldlals  method=1.4×14×2×(25025.52)1.61  g =48.80%\begin{array}{c} {\rm{\% }}\;{\rm{of}}\;{{\rm{N}}_{\rm{2}}}\;{\rm{by}}\;{\rm{Kjeldlal's}}\;{\rm{method}} = \dfrac{{1.4 \times \dfrac{1}{4} \times 2 \times \left( {\dfrac{{250 - 25.5}}{2}} \right)}}{{{\rm{1}}{\rm{.61}}\;{\rm{g}}}}\\\ = 48.80\% \end{array}

Therefore, the percentage of nitrogen in an organic compound analysis by Kjeldahl method is 48.80%48.80\% .

Note: :: The Kjeldahl method is used for the quantitative determination of nitrogen containing compounds that is protein, amines and several organic compounds. It is used to evaluate the quantity of protein in the beer.