Question
Question: Find the number of negative terms in the sequence : \({x_n} = \dfrac{{{}_{}^{n + 4}{P_4}}}{{{P_{n ...
Find the number of negative terms in the sequence :
xn=Pn+2n+4P4−4Pn143
Solution
In the given question the term Pn and Pn+2 stands for n+2Pn+2 and nPn respectively. Therefore , we know that for any permutation expression nPn=P!. Now solve it using a simple factorial rule.
Complete step by step answer:
We can write the given equation also as : -
xn=n+2Pn+2n+4P4−4nPn143
Now using the formula of permutation
nPr=(n−r)!n!
Substituting the values we get,
xn=(n+2)!(n−4−4)!(n+4)!−4n!143
⇒xn=(n+2)!n!(n+4)!−4n!143
Further solving the factorial in the numerator we get,
xn=(n+2)!n!(n+4)(n+3)(n+2)(n+1)n!−4.n!143
xn=(n+2)!(n+4)(n+3)(n+2)(n+1)−4.n!143
Further solving the factorial in the denominator we get,
xn=(n+2)(n+1)n!(n+4)(n+3)(n+2)(n+1)−4.n!143
⇒xn=n!(n+4)(n+3)−4.n!143
On taking L . C . M , we get
xn=4.n!(4n2+28n−95)
Now , since we have to find negative terms in xn , so xn will be less zero .
Therefore , xn=4.n!(4n2+28n−95)<0
xn=(4n2+28n−95)<0 , for solving the value of n we factorize the expression.
The given could be satisfied for the values n=1,2.
Therefore , on putting values of n in equation , we get
∴x1=−463 and x2=−823 .
So, there are two negative values for the given sequence.
Note: If n and r are positive integer such that 1⩽r⩽n , then the number of all permutation of n distinct things , taken r at a time is denoted by symbol P(n,r) or nPr. It should be noted that in permutations , the order of arrangement is taken into account when the order is changed , a different permutation is obtained. In permutations , if there are two jobs such that one of them can be completed in n ways , and when it has been completed in any one of these n ways , second job can be completed in r, then the two jobs succession can be completed in n×r ways.