Question

Find the number of atoms per unit cell if edge length is 300pm, density = 3 g/cm3 , molecular mass = 40 g(nearest integer)

Answer 1

$\text{The number of atoms per unit cell is}$:

$Z=\frac{3}{40}\times6\times0.1\times(4.05)^3$
$\approx 3.056$
$\approx3$

$\text{The correct answer is 3.}$